24k^2-4=0

Solution for 24k^2-4=0 equation:

24k^2-4=0

a = 24; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·24·(-4)
Δ = 384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{384}=\sqrt{64*6}=\sqrt{64}*\sqrt{6}=8\sqrt{6}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{6}}{2*24}=\frac{0-8\sqrt{6}}{48}
=-\frac{8\sqrt{6}}{48}
=-\frac{\sqrt{6}}{6}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{6}}{2*24}=\frac{0+8\sqrt{6}}{48}
=\frac{8\sqrt{6}}{48}
=\frac{\sqrt{6}}{6}
$